The Bold and the Beautiful (B&B) spoilers reveal that on the October 13 episode, Will Spencer (Crew Morrow) was confirmed as Luna Nozawa’s (Lisa Yamada) baby daddy. Oy vey all day.

Who Will Raise Luna’s Baby?

Luna is in no way equipped to be a mom. Her life is a hot mess and she will be in jail for the foreseeable future. That decision was made by Electra Forrester (Laneya Grace) who took it upon herself to see that Will’s assaulter got what is coming to her.

We think that custody of the child will be a contentious issue. Luna’s dad Finn Finnegan (Tanner Novlan) feels guilty about not raising her so he could decide to make things right by raising his grandchild.

Then there are the other set of grandparents, Bill Spencer (Don Diamont) and Katie Logan (Heather Tom). We suspect they will not be silent in this matter.

Bill Is Guilty

Bill also carries guilt for being the one who got Luna out of prison which led to her assaulting his drunk son, resulting in this stupendous pregnancy.

Bill will want to protect his son AND his grandchild at the same time. Given his ego, it’s easy to expect him to want to raise the child.

But what would Steffy Forrester (Jacqueline MacInnes Wood) and Katie have to say about their husbands’ possible custody bids?

Will Steffy and Katie Make a Compromise?

Steffy will reel when she learns what has transpired while she was out of town. She detests Luna, but she loves Finn.

Luna tried to kill her, but Steffy is a logical and fair person. After the dust settles she may concede that Finn deserves a second chance to raise a close relative.

As for Katie, she is already invested in the child’s best interest because her son’s life has been turned upside down. While she detests Luna, she would want what is best for Will’s baby.

And if Bill decides that the best thing is for them to raise the child, how could she disagree? Katie is all about family, and Luna’s child is her grandchild.

Tell us B&B fans, do you think the grandparents of Luna’s unborn baby have what it takes to raise her child?